Find the sum of first five multiples of 3

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WebTamang sagot sa tanong: 3. Find the sum of all multiples of 3 between 5 and 64 5. Find the sum of the first twelve terms of the arithmetic serieswhose general term is an = 5 + … WebWhat is the sum of the first 10 terms? 3. Find the sum of the first 25 multiples of 8. 11. find the sum of the first 25 multiples of 8; 12. 17. Find the sum of the first 25 …

Find the mean of the first five multiples of 3. - Vedantu

WebFirst term (a)=3 Common difference (d)=3 No. of terms (n)=8 Sum of terms (S n)=? As we know that, in an A.P., S n= 2n[2a+(n−1)d] ∴S 8= 28[2×3+(8−1)×3] ⇒S 8=4×(6+21) ⇒S 8=4×27=108 Was this answer helpful? 0 0 Similar questions Find the sum of the first 10 terms of the A.P. 4+6+8+ Medium View solution > WebApr 4, 2024 · Therefore the mean of the first five multiples of 3 is 9. Note: This problem can be solved in another method. We know that the first five multiples of 3 are 3, 6, 9, … sarvepalli radhakrishnan also known as

Find the sum of first five multiples of 3. - YouTube

WebJun 14, 2010 · The first 5 multiples of 3 are as follows: 3, 6, 9, 12, 15. ... The sum or difference of p and q is the of the x-term in the trinomial. A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials. WebIt is obtained by adding the same fixed number to its previous term. From the question, The first five multiples of 3 are 3, 6, 9,12 and 15. First term, a = 3, common difference, d = … Web18. The sum of first five multiples of 3 is(a) 45 (b) 55 (c) 65 (d) 75For Short Notes, Revision Notes And NCERT Solution.Visit Us at- www.kwatratuitioncen... shottons of hartlepool

The sum of first five multiples of 3 is (A) 45 (B) 55 (C) 65 (D) 75

Multiples of 17 - What are the multiples of 17? [Solved] - Cuemath

WebTamang sagot sa tanong: 3. Find the sum of all multiples of 3 between 5 and 64 5. Find the sum of the first twelve terms of the arithmetic serieswhose general term is an = 5 + 3n.6. Find the first 40 terms of the arithmetic series 1st and 3rd termsare 15 and 21 respectively.7. Find the sum of the first 50 odd natural numbers8. What is the sum of … WebFind the sum of all the terms of the series. The first five multiples of 3 are: 3, 6, 9, 12, 15. Sum = 3 + 6 + 9 + 12 + 15 = 45. Hence, the sum of the first five multiples of 3 is 45. … sarver facebookWebJan 21, 2015 · You are counting some numbers twice. What you have to do is add inside one for loop, and use an if-else statement where if you find multiples of 3, you do not … sarvepalli radhakrishnan university bhopal

"WebSep 7, 2024 · Find the sum of all the multiples of 3 or 5 below 1000. Here's my solution: sum = 0 for n in range(0, 1000): if n % 3 == 0 or n % 5 == 0: sum += n print(sum) The program works fine. What I want to get from a code review: ... The first being the “example” data in the problem itself; the second being the dataset you are being asked to solve. ... " - Find the sum of first five multiples of 3

Find the sum of first five multiples of 3

The sum of first five multiples of 3 is - Cuemath

WebMar 18, 2024 · Therefore, the sum of the first five multiples of 3 can be written as: S 5 = 5 2 [ 2 ( 3) + ( 5 − 1) ( 3)] ⇒ 5 2 [ 6 + 4 ( 3)] ⇒ 5 2 [ 6 + 12] ⇒ 5 2 [ 18] ⇒ 5 × 9 ⇒ 45. … WebJun 10, 2024 · Just use the A.P and the answer will be: (sum of multiple of 3) + (sum of multiple of 5) - (sum of multiple of 15) Use this formula to calculate the sum = n (a + l) / …

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WebMar 18, 2024 · Therefore, the sum of the first five multiples of 3 can be written as: S 5 = 5 2 [ 2 ( 3) + ( 5 − 1) ( 3)] ⇒ 5 2 [ 6 + 4 ( 3)] ⇒ 5 2 [ 6 + 12] ⇒ 5 2 [ 18] ⇒ 5 × 9 ⇒ 45. Therefore, we can write that the sum of the first five multiples of 3 is 45. Hence, option (A) is the correct option. Note: In this question, we can also find the ... WebFor example, the multiples of 3 are calculated 3x1, 3x2, 3x3, 3x4, 3x5, etc., which equal 3, 6, 9, 12, 15, etc. You can designate a minimum value to generate multiples greater than a number. For example, to find 100 …

WebOct 15, 2024 · In the original solution, for numbers under 1000, we need to loop 333 times, for numbers under 10000, we need to loop 3333 times,... It doesn't scale well. For the other solution, there are the same number of operations each time. Share Improve this answer answered Oct 15, 2024 at 8:07 AlanT 3,589 15 18 1 WebWhat is the sum of the first 10 terms? 3. Find the sum of the first 25 multiples of 8. 11. find the sum of the first 25 multiples of 8; 12. 17. Find the sum of the first 25 multiples of 8.A. 500C. 2600B. 2500D. 5200 13. . find the sum of first 25 multiples of 8; 14. Find the sum of the first 25 multiples 8; 15. D. Find the sum of the first 25 ...

WebSep 2, 2015 · We subtract the sum_fifteens twice because they are going to appear once in the sum_three_multiples (e.g. ..., 9, 12, 15, 18, ...) and once in the sum_five_multiples (e.g. 5, 15, 20, ...). So, something we notice about the sum of the multiples of some number between a range is that there is a lower multiple and a higher multiple.

WebConsider the first 5 multiples of 3 that is: 3, 6, 9, 12, 15 which is same as 3 multiplied by the first 5 integers (1, 2, 3, 4, 5). Sum of first 5 multiples of 3= = 3 + 6 + 9 + 12 + 15 = 3 * …

WebWe can also obtain multiples through the repeated addition of a number as many times as required. For example, the first five multiples of 5 can be written as: 5 × 1 = 5 5 × 2 = 10 or 5 + 5 = 8 {here 5 is added for twice} 5 × 3 = 15 or 5 + 5 + 5 = 15 {here 5 is added for thrice} 5 × 4 = 20 or 5 + 5 + 5 + 5 = 20 5 × 5 = 25 or 5 + 5 + 5 + 5 + 5 = 25 sarvepalli radhakrishnan teachers day quotesWebFind the sum of first ten multiples of 5. arithmetic progression cbse class-10 1 Answer +1 vote answered Sep 29, 2024 by KajalAgarwal (45.1k points) selected Oct 1, 2024 by Vikash Kumar Best answer Hence the sum = 275 ← Prev Question Next Question → Find MCQs & Mock Test Free JEE Main Mock Test Free NEET Mock Test Class 12 Chapterwise … shotton steel rfc facebookWebMar 2, 2012 · The statement of the problem is to sum the multiples of 3 and 5 below 1000, not up to and equal 1000. The correct answer is ∑ k 1 = 1 333 3 k 1 + ∑ k 2 = 1 199 5 k 2 − ∑ k 3 = 1 66 15 k 3 = 166833 + 99500 − 33165 = 233168, where we have the used the identity ∑ k = 1 n k = 1 2 n ( n + 1). Share Cite Follow edited Nov 7, 2010 at 19:03 sarver grocery storeWebIn this mini-lesson, we will calculate the multiples of 9 and we will learn some interesting facts about these multiples with solved examples and interactive questions. First five multiples of 9: 9, 18, 27, 36, 45 Prime Factorization of 9: 9 = 3 × 3 = 3 2 What Are the Multiples of 9? sarver indoor/outdoor lounge chair cushionWebNov 1, 2024 · The average of first five , 5’s multiples calculated as the sum of first 5 multiples of 5 divided by the total number. = Sum of 5/Total Numbers. Sum of First Five Multiples of = 5+10+15+20+25 = 75. Total Numbers = 5 = 75/5 = 15. The answer is 15. What is the Sum of First 8 Multiples of 5? The sum of the first 8 multiples of 5 is 180. shotton steel rfc twitterWebFind the sum of all the multiples of 3 or 5 below 1000. My reasoning is that since Since ⌊ 1000 3 ⌋ = 333 and ⌊ 1000 5 ⌋ = 200. This sum can be denoted as: ∑ n = 1 333 3 n + ∑ m = 1 200 5 m = 3 ∑ n = 1 333 n + 5 ∑ m = 1 200 m. Using the identity. ∑ i = 1 n i = n ( n + 1) 2. It can be solved analytically as. sarvepalli radhakrishnan quotes on educationWebThe multiples of 17 are the products obtained on multiplying the number 17 with other numbers. If we want the third multiple of 17, we can multiply 17 by 3 and get the multiple as 51. The first multiple of 17 = 17 × 1= 17 The 12th multiple of 17 = 17 × 12= 204 The 100th multiple of 17 = 17 × 100 = 1700 shottons kitchens hartlepool